Convert 10.0 mg/dL of calcium to International System of Units (SI). What is the result?

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Multiple Choice

Convert 10.0 mg/dL of calcium to International System of Units (SI). What is the result?

Explanation:
To convert calcium levels from mg/dL to the International System of Units (SI), which measures concentrations in mmol/L, you start with the molecular weight of calcium (Ca), which is approximately 40.08 g/mol. First, note that 10.0 mg/dL can also be expressed as 10.0 mg in 100 mL of solution. To convert this to grams, divide by 1000, so 10.0 mg = 0.010 g. Next, to find the concentration in grams per liter, convert 100 mL to liters. Thus, 0.010 g in 0.1 L (100 mL) translates to: \[ \text{Concentration in g/L} = \frac{0.010 \text{ g}}{0.1 \text{ L}} = 0.1 \text{ g/L} \] Now, to convert grams to moles, using the molecular weight of calcium (40.08 g/mol): \[ \text{Moles of Ca} = \frac{0.1 \text{ g}}{40.08 \text{ g/mol}} \approx 0.00249 \text{

To convert calcium levels from mg/dL to the International System of Units (SI), which measures concentrations in mmol/L, you start with the molecular weight of calcium (Ca), which is approximately 40.08 g/mol.

First, note that 10.0 mg/dL can also be expressed as 10.0 mg in 100 mL of solution. To convert this to grams, divide by 1000, so 10.0 mg = 0.010 g.

Next, to find the concentration in grams per liter, convert 100 mL to liters. Thus, 0.010 g in 0.1 L (100 mL) translates to:

[

\text{Concentration in g/L} = \frac{0.010 \text{ g}}{0.1 \text{ L}} = 0.1 \text{ g/L}

]

Now, to convert grams to moles, using the molecular weight of calcium (40.08 g/mol):

[

\text{Moles of Ca} = \frac{0.1 \text{ g}}{40.08 \text{ g/mol}} \approx 0.00249 \text{

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