How many grams of CuSO4 • 5H2O are needed to prepare 1.0 L of a stock solution containing 9.6 g of copper II sulfate?

How many grams of CuSO4 • 5H2O are needed to prepare 1.0 L of a stock solution containing 9.6 g of copper II sulfate?

• A. 5.4 g
• B. 6.1 g
• C. 15.0 g
• D. 17.0 g

Answer: (C)

To determine how many grams of CuSO4•5H2O (copper(II) sulfate pentahydrate) are needed to prepare a solution containing 9.6 g of copper(II) sulfate, it's important to understand the relationship between the anhydrous salt and its hydrated form. Copper(II) sulfate (CuSO4) has a molar mass of approximately 159.61 g/mol. The hydrated form, CuSO4•5H2O, includes five water molecules, which contributes additional mass. The molar mass of CuSO4•5H2O is approximately: - Molar mass of CuSO4: 159.61 g/mol - Molar mass of water (H2O): 18.02 g/mol - Molar mass of 5H2O: 5 x 18.02 g/mol = 90.1 g/mol - Total molar mass of CuSO4•5H2O: 159.61 g/mol + 90.1 g/mol = 249.71 g/mol In order to prepare the solution containing 9.6 g of copper(II) sulfate, we first need to find out how many

To determine how many grams of CuSO4•5H2O (copper(II) sulfate pentahydrate) are needed to prepare a solution containing 9.6 g of copper(II) sulfate, it's important to understand the relationship between the anhydrous salt and its hydrated form.

Copper(II) sulfate (CuSO4) has a molar mass of approximately 159.61 g/mol. The hydrated form, CuSO4•5H2O, includes five water molecules, which contributes additional mass. The molar mass of CuSO4•5H2O is approximately:

• Molar mass of CuSO4: 159.61 g/mol

• Molar mass of water (H2O): 18.02 g/mol

• Molar mass of 5H2O: 5 x 18.02 g/mol = 90.1 g/mol

• Total molar mass of CuSO4•5H2O: 159.61 g/mol + 90.1 g/mol = 249.71 g/mol

In order to prepare the solution containing 9.6 g of copper(II) sulfate, we first need to find out how many